Q1) \(x + 6\over 3\) - \(x + 9\over 5\) = [ \(2 x + 3\over 15\) ]

Q1) \(8\over x+ 3\) - \(6\over x +2\) = [ \(2 x -2\over x^{2}+ 5 x +6 \)]

Q1) \(7\over x+ 2\) - \(2\over x -7\) = [ \(5 x -53\over x^{2}-5x -14 \)]

Q2) \(x + 8\over 4\) + \(x + 10\over 5\) = [ \(9 x + 80\over 20\) ]

Q2) \(10\over x+ 3\) - \(8\over x +5\) = [ \(2 x + 26\over x^{2}+ 8 x +15 \)]

Q2) \(6\over x+ 4\) - \(3\over x -8\) = [ \(3 x -60\over x^{2}-4x -32 \)]

Q3) \(x + 8\over 4\) + \(x + 6\over 3\) = [ \(7 x + 48\over 12\) ]

Q3) \(10\over x+ 4\) - \(8\over x +2\) = [ \(2 x -12\over x^{2}+ 6 x +8 \)]

Q3) \(5\over x+ 4\) + \(5\over x -9\) = [ \(10 x -25\over x^{2}-5x -36 \)]

Q4) \(x + 4\over 3\) - \(x + 10\over 5\) = [ \(2 x -10\over 15\) ]

Q4) \(8\over x+ 6\) + \(4\over x +2\) = [ \(12 x + 40\over x^{2}+ 8 x +12 \)]

Q4) \(9\over x+ 3\) + \(6\over x -5\) = [ \(15 x -27\over x^{2}-2x -15 \)]

Q5) \(x + 9\over 5\) + \(x + 10\over 2\) = [ \(7 x + 68\over 10\) ]

Q5) \(9\over x+ 8\) - \(7\over x +4\) = [ \(2 x -20\over x^{2}+ 12 x +32 \)]

Q5) \(9\over x+ 6\) + \(9\over x +8\) = [ \(18 x + 126\over x^{2}+14x +48 \)]

Q6) \(x + 7\over 4\) + \(x + 10\over 4\) = [ \(2 x + 17\over 4\) ]

Q6) \(10\over x+ 2\) - \(7\over x +5\) = [ \(3 x + 36\over x^{2}+ 7 x +10 \)]

Q6) \(10\over x+ 6\) - \(4\over x -6\) = [ \(6 x -84\over x^{2} -36 \)]

Q7) \(x + 10\over 2\) - \(x + 9\over 6\) = [ \(2 x + 21\over 6\) ]

Q7) \(9\over x+ 3\) + \(6\over x +2\) = [ \(15 x + 36\over x^{2}+ 5 x +6 \)]

Q7) \(10\over x+ 5\) - \(3\over x -10\) = [ \(7 x -115\over x^{2}-5x -50 \)]

Q8) \(x + 7\over 2\) + \(x + 5\over 4\) = [ \(3 x + 19\over 4\) ]

Q8) \(10\over x+ 7\) + \(7\over x +2\) = [ \(17 x + 69\over x^{2}+ 9 x +14 \)]

Q8) \(8\over x+ 7\) - \(4\over x -10\) = [ \(4 x -108\over x^{2}-3x -70 \)]

Q9) \(x + 8\over 2\) - \(x + 10\over 5\) = [ \(3 x + 20\over 10\) ]

Q9) \(10\over x+ 3\) - \(8\over x +4\) = [ \(2 x + 16\over x^{2}+ 7 x +12 \)]

Q9) \(10\over x+ 6\) + \(10\over x -2\) = [ \(20 x + 40\over x^{2}+4x -12 \)]

Q10) \(x + 9\over 6\) + \(x + 10\over 5\) = [ \(11x + 105\over 30\) ]

Q10) \(6\over x+ 4\) + \(8\over x +6\) = [ \(14 x + 68\over x^{2}+ 10 x +24 \)]

Q10) \(9\over x+ 8\) - \(5\over x -3\) = [ \(4 x -67\over x^{2}+5x -24 \)]