Q1) \(x + 5\over 2\) - \(x + 10\over 6\) = [ \(2 x + 5\over 6\) ]

Q1) \(10\over x+ 3\) + \(8\over x +5\) = [ \(18 x + 74\over x^{2}+ 8 x +15 \)]

Q1) \(10\over x+ 9\) - \(8\over x -5\) = [ \(2 x -122\over x^{2}+4x -45 \)]

Q2) \(x + 6\over 3\) - \(x + 8\over 7\) = [ \(4 x + 18\over 21\) ]

Q2) \(6\over x+ 2\) + \(8\over x +6\) = [ \(14 x + 52\over x^{2}+ 8 x +12 \)]

Q2) \(9\over x+ 7\) - \(3\over x -10\) = [ \(6 x -111\over x^{2}-3x -70 \)]

Q3) \(x + 7\over 3\) - \(x + 9\over 5\) = [ \(2 x + 8\over 15\) ]

Q3) \(9\over x+ 5\) - \(7\over x +2\) = [ \(2 x -17\over x^{2}+ 7 x +10 \)]

Q3) \(9\over x+ 5\) + \(5\over x +4\) = [ \(14 x + 61\over x^{2}+9x +20 \)]

Q4) \(x + 10\over 5\) - \(x + 10\over 9\) = [ \(4 x + 40\over 45\) ]

Q4) \(10\over x+ 5\) - \(7\over x +5\) = [ \(3 x + 15\over x^{2}+ 10 x +25 \)]

Q4) \(8\over x+ 7\) - \(4\over x +2\) = [ \(4 x -12\over x^{2}+9x +14 \)]

Q5) \(x + 10\over 3\) - \(x + 8\over 5\) = [ \(2 x + 26\over 15\) ]

Q5) \(10\over x+ 8\) + \(10\over x +2\) = [ \(20 x + 100\over x^{2}+ 10 x +16 \)]

Q5) \(7\over x+ 3\) - \(5\over x -7\) = [ \(2 x -64\over x^{2}-4x -21 \)]

Q6) \(x + 5\over 2\) - \(x + 8\over 5\) = [ \(3 x + 9\over 10\) ]

Q6) \(8\over x+ 6\) - \(4\over x +3\) = [ \(4 x\over x^{2}+ 9 x +18 \)]

Q6) \(5\over x+ 3\) - \(3\over x -2\) = [ \(2 x -19\over x^{2}+x -6 \)]

Q7) \(x + 7\over 2\) + \(x + 4\over 3\) = [ \(5 x + 29\over 6\) ]

Q7) \(10\over x+ 4\) - \(6\over x +4\) = [ \(4 x + 16\over x^{2}+ 8 x +16 \)]

Q7) \(8\over x+ 5\) - \(5\over x -4\) = [ \(3 x -57\over x^{2}+x -20 \)]

Q8) \(x + 8\over 3\) + \(x + 8\over 2\) = [ \(5 x + 40\over 6\) ]

Q8) \(8\over x+ 2\) - \(6\over x +5\) = [ \(2 x + 28\over x^{2}+ 7 x +10 \)]

Q8) \(10\over x+ 8\) - \(6\over x -2\) = [ \(4 x -68\over x^{2}+6x -16 \)]

Q9) \(x + 9\over 4\) + \(x + 10\over 5\) = [ \(9 x + 85\over 20\) ]

Q9) \(10\over x+ 4\) - \(7\over x +3\) = [ \(3 x + 2\over x^{2}+ 7 x +12 \)]

Q9) \(8\over x+ 3\) - \(5\over x -2\) = [ \(3 x -31\over x^{2}+x -6 \)]

Q10) \(x + 10\over 8\) + \(x + 9\over 4\) = [ \(3 x + 28\over 8\) ]

Q10) \(10\over x+ 9\) - \(4\over x +2\) = [ \(6 x -16\over x^{2}+ 11x +18 \)]

Q10) \(7\over x+ 4\) + \(3\over x -5\) = [ \(10 x -23\over x^{2}-x -20 \)]