Q1) There are 10 yellow beads ,and 3 green beads in a bag.
a) What is the probability of picking a yellow bead?
b) What is the probability of picking a green bead?
[ a) P(yellow)=\(\frac{10}{13}\).
b) P(green)=\(\frac{3}{13}\).
]

Q1) There were 4 yellow beads ,and 10 red beads in a box . Two beads were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{6}{91}\) ]

Q1) There are 9 yellow pens ,and some red pens in a packet . 2 extra red pens were added. Two pens were picked at random and not replaced. The probability they were both yellow was \(\frac{12}{35}\). How many red pens were there to begin with ?
[ 4 ]

Q2) There are 6 blue apples, 7 are green apples, and 7 are yellow apples in a bag
a) What is the probability of picking a blue one?
b) What is the probability of picking a green one?
c) What is the probability of picking a yellow one?
[ a) P(blue)=\(\frac{3}{10}\).
b) P(green)=\(\frac{7}{20}\).
c) P(yellow)=\(\frac{7}{20}\).
]

Q2) There were 9 yellow pencils ,and 6 red pencils in a box . Two pencils were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{12}{35}\) ]

Q2) There are 4 blue pencils ,and some red pencils in a bag . 6 extra red pencils were added. Two pencils were picked at random and not replaced. The probability they were both blue was \(\frac{6}{91}\). How many red pencils were there to begin with ?
[ 4 ]

Q3) There are 7 red beads ,and 6 purple beads in a bag.
a) What is the probability of picking a red bead?
b) What is the probability of picking a purple bead?
[ a) P(red)=\(\frac{7}{13}\).
b) P(purple)=\(\frac{6}{13}\).
]

Q3) There were 10 purple pencils ,and 6 yellow pencils in a packet . Two pencils were picked and not replaced. What was the probability they were both purple ?
[ \(\frac{3}{8}\) ]

Q3) There were 7 purple apples ,and some green apples in a bag . Two apples were picked at random and not replaced. The probability they were both purple was \(\frac{7}{15}\). How many green apples were there ?
[ 3 ]

Q4) There are 9 purple beads ,and 7 green beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a green bead?
[ a) P(purple)=\(\frac{9}{16}\).
b) P(green)=\(\frac{7}{16}\).
]

Q4) There were 9 yellow sweets ,and 6 purple sweets in a bag . Two sweets were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{12}{35}\) ]

Q4) There were 5 green beads ,and some red beads in a tin . Two beads were picked at random and not replaced. The probability they were both green was \(\frac{10}{21}\). How many red beads were there ?
[ 2 ]

Q5) There are 4 purple pens, 7 are yellow pens, and 6 are red pens in a box
a) What is the probability of picking a purple one?
b) What is the probability of picking a yellow one?
c) What is the probability of picking a red one?
[ a) P(purple)=\(\frac{4}{17}\).
b) P(yellow)=\(\frac{7}{17}\).
c) P(red)=\(\frac{6}{17}\).
]

Q5) There were 9 purple sweets ,and 10 red sweets in a packet . Two sweets were picked and not replaced. What was the probability they were both purple ?
[ \(\frac{4}{19}\) ]

Q5) There are 7 yellow sweets ,and some green sweets in a bag . 3 extra green sweets were added. Two sweets were picked at random and not replaced. The probability they were both yellow was \(\frac{7}{22}\). How many green sweets were there to begin with ?
[ 2 ]