Q1) \(x + 9\over 3\) x \(x + 10\over 5\) = [ \(x^2 + 19 x + 90\over 15\) ]

Q1) \(x + 3\over 1\) ÷ \({ x + 5} \over 3 \) = [ \(3( x + 3) \over( x + 5)\) ]

Q1) \(x + 10\over 10\) ÷ \( x + 10\over x + 6\) = [ \(x + 6\over 10\) ]

Q2) \(x + 6\over 2\) ÷ \(3 \over {x + 4}\) = [ \(x^2 + 10 x + 24\over 6\) ]

Q2) \(x + 8\over 5\) ÷ \({ x + 6} \over 4 \) = [ \(4( x + 8) \over 5 ( x + 6)\) ]

Q2) \(x + 7\over 7\) x \(x + 7\over x + 7\) = [ \(x + 7\over 7\) ]

Q3) \(x + 7\over 10\) x \(x + 2\over 7\) = [ \(x^2 + 9 x + 14\over 70\) ]

Q3) \(x + 10\over 1\) x \(1 \over{ x + 8}\) = [ \(1( x + 10) \over( x + 8)\) ]

Q3) \(x + 10\over 3\) ÷ \( x + 10\over x + 6\) = [ \(x + 6\over 3\) ]

Q4) \(x + 8\over 3\) x \(x + 4\over 5\) = [ \(x^2 + 12 x + 32\over 15\) ]

Q4) \(x + 2\over 2\) ÷ \({ x + 8} \over 1 \) = [ \(1( x + 2) \over 2 ( x + 8)\) ]

Q4) \(x + 6\over 8\) x \(x + 6\over x + 6\) = [ \(x + 6\over 8\) ]

Q5) \(x + 8\over 6\) x \(x + 10\over 7\) = [ \(x^2 + 18 x + 80\over 42\) ]

Q5) \(x + 7\over 8\) ÷ \({ x + 3} \over 7 \) = [ \(7( x + 7) \over 8 ( x + 3)\) ]

Q5) \(x + 9\over 3\) ÷ \( x + 9\over x + 1\) = [ \(x + 1\over 3\) ]

Q6) \(x + 4\over 6\) ÷ \(4 \over {x + 9}\) = [ \(x^2 + 13 x + 36\over 24\) ]

Q6) \(x + 4\over 2\) x \(5 \over{ x + 1}\) = [ \(5( x + 4) \over 2 ( x + 1)\) ]

Q6) \(x + 2\over 8\) ÷ \( x + 2\over x + 2\) = [ \(x + 2\over 8\) ]

Q7) \(x + 6\over 6\) ÷ \(8 \over {x + 3}\) = [ \(x^2 + 9 x + 18\over 48\) ]

Q7) \(x + 2\over 1\) ÷ \({ x + 9} \over 1 \) = [ \(1( x + 2) \over( x + 9)\) ]

Q7) \(x + 7\over 8\) x \(x + 4\over x + 7\) = [ \(x + 4\over 8\) ]

Q8) \(x + 3\over 2\) x \(x + 1\over 4\) = [ \(x^2 + 4 x + 3\over 8\) ]

Q8) \(x + 3\over 1\) ÷ \({ x + 6} \over 5 \) = [ \(5( x + 3) \over( x + 6)\) ]

Q8) \(x + 6\over 3\) x \(x + 1\over x + 6\) = [ \(x + 1\over 3\) ]

Q9) \(x + 10\over 6\) ÷ \(4 \over {x + 9}\) = [ \(x^2 + 19 x + 90\over 24\) ]

Q9) \(x + 5\over 2\) x \(1 \over{ x + 1}\) = [ \(1( x + 5) \over 2 ( x + 1)\) ]

Q9) \(x + 6\over 10\) ÷ \( x + 6\over x + 5\) = [ \(x + 5\over 10\) ]

Q10) \(x + 2\over 9\) ÷ \(5 \over {x + 8}\) = [ \(x^2 + 10 x + 16\over 45\) ]

Q10) \(x + 3\over 1\) x \(1 \over{ x + 5}\) = [ \(1( x + 3) \over( x + 5)\) ]

Q10) \(x + 4\over 2\) ÷ \( x + 4\over x + 10\) = [ \(x + 10\over 2\) ]