Mr Daniels Maths
Conversions: Improper to Mixed fractions

Set 1

Set 2

Set 3

Q1) \(14\over3\)= [ 4\(\frac{2}{3}\) ]

Q1) \(56\over5\)= [ 11\(\frac{1}{5}\)]

Q1) \(91\over11\) = [ 8\(\frac{3}{11}\)]

Q2) \(11\over3\)= [ 3\(\frac{2}{3}\) ]

Q2) \(67\over6\)= [ 11\(\frac{1}{6}\)]

Q2) \(133\over10\) = [ 13\(\frac{3}{10}\)]

Q3) \(11\over2\)= [ 5\(\frac{1}{2}\) ]

Q3) \(55\over6\)= [ 9\(\frac{1}{6}\)]

Q3) \(119\over11\) = [ 10\(\frac{9}{11}\)]

Q4) \(10\over3\)= [ 3\(\frac{1}{3}\) ]

Q4) \(57\over5\)= [ 11\(\frac{2}{5}\)]

Q4) \(77\over12\) = [ 6\(\frac{5}{12}\)]

Q5) \(19\over3\)= [ 6\(\frac{1}{3}\) ]

Q5) \(31\over6\)= [ 5\(\frac{1}{6}\)]

Q5) \(91\over10\) = [ 9\(\frac{1}{10}\)]

Q6) \(17\over3\)= [ 5\(\frac{2}{3}\) ]

Q6) \(69\over5\)= [ 13\(\frac{4}{5}\)]

Q6) \(119\over12\) = [ 9\(\frac{11}{12}\)]

Q7) \(20\over3\)= [ 6\(\frac{2}{3}\) ]

Q7) \(29\over6\)= [ 4\(\frac{5}{6}\)]

Q7) \(133\over8\) = [ 16\(\frac{5}{8}\)]

Q8) \(16\over3\)= [ 5\(\frac{1}{3}\) ]

Q8) \(59\over6\)= [ 9\(\frac{5}{6}\)]

Q8) \(70\over11\) = [ 6\(\frac{4}{11}\)]

Q9) \(13\over3\)= [ 4\(\frac{1}{3}\) ]

Q9) \(22\over5\)= [ 4\(\frac{2}{5}\)]

Q9) \(112\over9\) = [ 12\(\frac{4}{9}\)]

Q10) \(13\over2\)= [ 6\(\frac{1}{2}\) ]

Q10) \(44\over5\)= [ 8\(\frac{4}{5}\)]

Q10) \(56\over9\) = [ 6\(\frac{2}{9}\)]