Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q1) 3\(\frac{5}{6}\)= [ \(23\over6\) ]

Q1) 3\(\frac{2}{11}\)= [ \(35\over11\) ]

Q2) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q2) 11\(\frac{1}{6}\)= [ \(67\over6\) ]

Q2) 7\(\frac{7}{11}\)= [ \(84\over11\) ]

Q3) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q3) 4\(\frac{5}{6}\)= [ \(29\over6\) ]

Q3) 11\(\frac{9}{10}\)= [ \(119\over10\) ]

Q4) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q4) 9\(\frac{5}{6}\)= [ \(59\over6\) ]

Q4) 6\(\frac{1}{8}\)= [ \(49\over8\) ]

Q5) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q5) 10\(\frac{1}{5}\)= [ \(51\over5\) ]

Q5) 10\(\frac{8}{9}\)= [ \(98\over9\) ]

Q6) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q6) 5\(\frac{1}{5}\)= [ \(26\over5\) ]

Q6) 12\(\frac{1}{11}\)= [ \(133\over11\) ]

Q7) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q7) 8\(\frac{1}{5}\)= [ \(41\over5\) ]

Q7) 6\(\frac{3}{10}\)= [ \(63\over10\) ]

Q8) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q8) 5\(\frac{4}{5}\)= [ \(29\over5\) ]

Q8) 3\(\frac{8}{9}\)= [ \(35\over9\) ]

Q9) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q9) 4\(\frac{3}{5}\)= [ \(23\over5\) ]

Q9) 13\(\frac{1}{8}\)= [ \(105\over8\) ]

Q10) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q10) 12\(\frac{1}{5}\)= [ \(61\over5\) ]

Q10) 4\(\frac{3}{8}\)= [ \(35\over8\) ]