Mr Daniels Maths
Factorising Double Brackets 2

Set 1

Set 2

Set 3

Q1) Factorise \(x^2 -2x -80\). [ \((x + 8)(x -10)\)]

Q1) Factorise the following;
\(x^2 -4 =\) [ \((x -2)(x + 2)\)]

Q1) Factorise the following;
\(9 x^2 + 12 x+ 4= \)
[ \((3x + 2)(3x + 2)\)]

Q2) Factorise \(x^2 + 2x -8\). [ \((x + 4)(x -2)\)]

Q2) Factorise the following;
\(x^2 -169 =\) [ \((x -13)(x + 13)\)]

Q2) Factorise the following;
\(9 x^2 + 6 x+ 1= \)
[ \((3x + 1)(3x + 1)\)]

Q3) Factorise \(x^2 + 4x -12\). [ \((x + 6)(x -2)\)]

Q3) Factorise the following;
\(x^2 -225 =\) [ \((x -15)(x + 15)\)]

Q3) Factorise the following;
\(6 x^2 + 13 x+ 6= \)
[ \((3x + 2)(2x + 3)\)]

Q4) Factorise \(x^2 -x -6\). [ \((x + 2)(x -3)\)]

Q4) Factorise the following;
\(81x^2 -225 =\) [ \((9x + 15)(9x -15)\)]

Q4) Factorise the following;
\(6 x^2 + 11x+ 3= \)
[ \((3x + 1)(2x + 3)\)]

Q5) Factorise \(x^2 + 3x -40\). [ \((x + 8)(x -5)\)]

Q5) Factorise the following;
\(x^2 -100 =\) [ \((x + 10)(x -10)\)]

Q5) Factorise the following;
\(6 x^2 + 7 x+ 2= \)
[ \((3x + 2)(2x + 1)\)]

Q6) Factorise \(x^2 -2x -35\). [ \((x + 5)(x -7)\)]

Q6) Factorise the following;
\(x^2 -16 =\) [ \((x + 4)(x -4)\)]

Q6) Factorise the following;
\(8 x^2 + 10 x+ 3= \)
[ \((2x + 1)(4x + 3)\)]

Q7) Factorise \(x^2 -x -20\). [ \((x + 4)(x -5)\)]

Q7) Factorise the following;
\(x^2 -64 =\) [ \((x -8)(x + 8)\)]

Q7) Factorise the following;
\(8 x^2 + 22 x+ 5= \)
[ \((2x + 5)(4x + 1)\)]

Q8) Factorise \(x^2 + 3x -10\). [ \((x + 5)(x -2)\)]

Q8) Factorise the following;
\(x^2 -196 =\) [ \((x + 14)(x -14)\)]

Q8) Factorise the following;
\(8 x^2 + 14 x+ 5= \)
[ \((2x + 1)(4x + 5)\)]

Q9) Factorise \(x^2 -4x -12\). [ \((x + 2)(x -6)\)]

Q9) Factorise the following;
\(64x^2 -144 =\) [ \((8x -12)(8x + 12)\)]

Q9) Factorise the following;
\(8 x^2 + 14 x+ 3= \)
[ \((2x + 3)(4x + 1)\)]

Q10) Factorise \(x^2 + x -6\). [ \((x + 3)(x -2)\)]

Q10) Factorise the following;
\(x^2 -144 =\) [ \((x + 12)(x -12)\)]

Q10) Factorise the following;
\(6 x^2 + 11x+ 4= \)
[ \((2x + 1)(3x + 4)\)]