Q1) \(2\over3\) x \(9\over10\) = [ \(\frac{3}{5}\)]

Q1) \(2\over4\) x \(8\over10\) x \(30\over14\)= [ \(\frac{6}{7}\)]

Q1) \(2\over4\) x \(8\over9\) x \(18\over11\) + \(5\over9\)= [ 1\(\frac{28}{99}\)]

Q2) \(2\over4\) x \(8\over9\) = [ \(\frac{4}{9}\)]

Q2) \(2\over3\) x \(6\over8\) x \(16\over15\)= [ \(\frac{8}{15}\)]

Q2) \(2\over3\) x \(6\over8\) x \(24\over15\) + \(3\over8\)= [ 1\(\frac{7}{40}\)]

Q3) \(2\over4\)  \(\div\) \(9\over8\) =   [ \(\frac{4}{9}\)]

Q3) \(2\over4\) x \(8\over9\) \(\div\) \(14\over18\)= [ \(\frac{4}{7}\)]

Q3) \(2\over3\) x \(6\over8\) x \(24\over13\) - \(2\over8\)= [ \(\frac{35}{52}\)]

Q4) \(2\over4\)  \(\div\) \(10\over8\) =   [ \(\frac{2}{5}\)]

Q4) \(2\over3\) x \(6\over10\) x \(20\over14\)= [ \(\frac{4}{7}\)]

Q4) \(2\over3\) x \(6\over7\) x \(14\over12\) + \(7\over7\)= [ 1\(\frac{2}{3}\)]

Q5) \(2\over4\) x \(8\over9\) = [ \(\frac{4}{9}\)]

Q5) \(2\over4\) x \(8\over9\) x \(27\over14\)= [ \(\frac{6}{7}\)]

Q5) \(3\over4\) x \(8\over10\) x \(20\over13\) + \(6\over10\)= [ 1\(\frac{34}{65}\)]

Q6) \(2\over4\)  \(\div\) \(10\over8\) =   [ \(\frac{2}{5}\)]

Q6) \(2\over4\) x \(8\over10\) x \(20\over9\)= [ \(\frac{8}{9}\)]

Q6) \(2\over3\) x \(6\over9\) x \(18\over14\) - \(6\over9\)= [ -\(\frac{2}{21}\)]

Q7) \(2\over4\)  \(\div\) \(10\over8\) =   [ \(\frac{2}{5}\)]

Q7) \(2\over3\) x \(6\over8\) x \(24\over13\)= [ \(\frac{12}{13}\)]

Q7) \(2\over3\) x \(6\over7\) + \(5\over7\)= [ 1\(\frac{2}{7}\)]

Q8) \(2\over4\)  \(\div\) \(10\over8\) =   [ \(\frac{2}{5}\)]

Q8) \(2\over3\) x \(6\over8\) \(\div\) \(13\over16\)= [ \(\frac{8}{13}\)]

Q8) \(2\over3\) x \(6\over7\) x \(14\over10\) + \(5\over7\)= [ 1\(\frac{18}{35}\)]

Q9) \(2\over3\) x \(6\over9\) = [ \(\frac{4}{9}\)]

Q9) \(2\over3\) x \(6\over8\) x \(16\over13\)= [ \(\frac{8}{13}\)]

Q9) \(2\over3\) x \(6\over9\) x \(18\over15\) + \(5\over9\)= [ 1\(\frac{4}{45}\)]

Q10) \(3\over4\)  \(\div\) \(9\over8\) =   [ \(\frac{2}{3}\)]

Q10) \(2\over4\) x \(8\over9\) \(\div\) \(14\over27\)= [ \(\frac{6}{7}\)]

Q10) \(2\over3\) x \(6\over10\) x \(20\over10\) - \(5\over10\)= [ \(\frac{3}{10}\)]