Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{3}{5}\) - \(\frac{1}{2}\) = [ \(\frac{1}{10}\)]

Q1) 1\(\frac{1}{7}\) - \(\frac{1}{2}\) = [ \(\frac{9}{14}\)]

Q1) 2\(\frac{1}{3}\) - 1\(\frac{6}{7}\) = [ \(\frac{10}{21}\)]

Q2) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q2) 1\(\frac{1}{6}\) - \(\frac{2}{7}\) = [ \(\frac{37}{42}\)]

Q2) 1\(\frac{6}{7}\) - 1\(\frac{1}{3}\) = [ \(\frac{11}{21}\)]

Q3) \(\frac{3}{4}\) - \(\frac{2}{3}\) = [ \(\frac{1}{12}\)]

Q3) 1\(\frac{1}{8}\) - \(\frac{3}{5}\) = [ \(\frac{21}{40}\)]

Q3) 3\(\frac{1}{4}\) - 1\(\frac{3}{5}\) = [ 1\(\frac{13}{20}\)]

Q4) \(\frac{2}{3}\) - \(\frac{1}{4}\) = [ \(\frac{5}{12}\)]

Q4) 1\(\frac{1}{4}\) - \(\frac{3}{4}\) = [ \(\frac{1}{2}\)]

Q4) 2\(\frac{1}{6}\) - 1\(\frac{3}{8}\) = [ \(\frac{19}{24}\)]

Q5) \(\frac{5}{8}\) - \(\frac{1}{3}\) = [ \(\frac{7}{24}\)]

Q5) 1\(\frac{1}{6}\) - \(\frac{2}{5}\) = [ \(\frac{23}{30}\)]

Q5) 2\(\frac{1}{2}\) - 1\(\frac{5}{6}\) = [ \(\frac{2}{3}\)]

Q6) \(\frac{6}{7}\) - \(\frac{1}{3}\) = [ \(\frac{11}{21}\)]

Q6) 1\(\frac{3}{7}\) - \(\frac{2}{3}\) = [ \(\frac{16}{21}\)]

Q6) 2\(\frac{1}{2}\) - 1\(\frac{5}{7}\) = [ \(\frac{11}{14}\)]

Q7) \(\frac{2}{3}\) - \(\frac{2}{7}\) = [ \(\frac{8}{21}\)]

Q7) 1\(\frac{1}{8}\) - \(\frac{5}{6}\) = [ \(\frac{7}{24}\)]

Q7) 1\(\frac{6}{7}\) - 1\(\frac{2}{3}\) = [ \(\frac{4}{21}\)]

Q8) \(\frac{4}{5}\) - \(\frac{5}{7}\) = [ \(\frac{3}{35}\)]

Q8) 1\(\frac{3}{4}\) - \(\frac{9}{10}\) = [ \(\frac{17}{20}\)]

Q8) 3\(\frac{1}{2}\) - 2\(\frac{1}{4}\) = [ 1\(\frac{1}{4}\)]

Q9) \(\frac{4}{5}\) - \(\frac{2}{3}\) = [ \(\frac{2}{15}\)]

Q9) 1\(\frac{1}{3}\) - \(\frac{2}{3}\) = [ \(\frac{2}{3}\)]

Q9) 3\(\frac{1}{2}\) - 1\(\frac{2}{3}\) = [ 1\(\frac{5}{6}\)]

Q10) \(\frac{3}{4}\) - \(\frac{1}{2}\) = [ \(\frac{1}{4}\)]

Q10) 1\(\frac{2}{5}\) - \(\frac{3}{4}\) = [ \(\frac{13}{20}\)]

Q10) 1\(\frac{3}{4}\) - 1\(\frac{1}{2}\) = [ \(\frac{1}{4}\)]