Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{2}{3}\) - \(\frac{2}{7}\) = [ \(\frac{8}{21}\)]

Q1) 1\(\frac{1}{5}\) - \(\frac{1}{2}\) = [ \(\frac{7}{10}\)]

Q1) 3\(\frac{2}{3}\) - 1\(\frac{2}{7}\) = [ 2\(\frac{8}{21}\)]

Q2) \(\frac{1}{2}\) - \(\frac{2}{7}\) = [ \(\frac{3}{14}\)]

Q2) 1\(\frac{1}{4}\) - \(\frac{3}{5}\) = [ \(\frac{13}{20}\)]

Q2) 3\(\frac{1}{2}\) - 1\(\frac{3}{4}\) = [ 1\(\frac{3}{4}\)]

Q3) \(\frac{5}{6}\) - \(\frac{5}{7}\) = [ \(\frac{5}{42}\)]

Q3) 1\(\frac{2}{3}\) - \(\frac{4}{5}\) = [ \(\frac{13}{15}\)]

Q3) 2\(\frac{1}{2}\) - 1\(\frac{4}{13}\) = [ 1\(\frac{5}{26}\)]

Q4) \(\frac{5}{6}\) - \(\frac{4}{7}\) = [ \(\frac{11}{42}\)]

Q4) 1\(\frac{1}{4}\) - \(\frac{2}{3}\) = [ \(\frac{7}{12}\)]

Q4) 3\(\frac{1}{2}\) - 1\(\frac{9}{19}\) = [ 2\(\frac{1}{38}\)]

Q5) \(\frac{3}{5}\) - \(\frac{1}{3}\) = [ \(\frac{4}{15}\)]

Q5) 1\(\frac{1}{2}\) - \(\frac{5}{8}\) = [ \(\frac{7}{8}\)]

Q5) 3\(\frac{1}{2}\) - 1\(\frac{3}{7}\) = [ 2\(\frac{1}{14}\)]

Q6) \(\frac{4}{5}\) - \(\frac{1}{2}\) = [ \(\frac{3}{10}\)]

Q6) 1\(\frac{2}{3}\) - \(\frac{3}{4}\) = [ \(\frac{11}{12}\)]

Q6) 3\(\frac{1}{2}\) - 1\(\frac{5}{6}\) = [ 1\(\frac{2}{3}\)]

Q7) \(\frac{4}{5}\) - \(\frac{2}{3}\) = [ \(\frac{2}{15}\)]

Q7) 1\(\frac{1}{2}\) - \(\frac{5}{9}\) = [ \(\frac{17}{18}\)]

Q7) 2\(\frac{2}{7}\) - 1\(\frac{3}{8}\) = [ \(\frac{51}{56}\)]

Q8) \(\frac{3}{4}\) - \(\frac{1}{2}\) = [ \(\frac{1}{4}\)]

Q8) 1\(\frac{1}{6}\) - \(\frac{2}{3}\) = [ \(\frac{1}{2}\)]

Q8) 3\(\frac{2}{3}\) - 1\(\frac{1}{3}\) = [ 2\(\frac{1}{3}\)]

Q9) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q9) 1\(\frac{2}{7}\) - \(\frac{2}{5}\) = [ \(\frac{31}{35}\)]

Q9) 5\(\frac{1}{2}\) - 1\(\frac{3}{4}\) = [ 3\(\frac{3}{4}\)]

Q10) \(\frac{5}{6}\) - \(\frac{3}{5}\) = [ \(\frac{7}{30}\)]

Q10) 1\(\frac{1}{3}\) - \(\frac{6}{7}\) = [ \(\frac{10}{21}\)]

Q10) 3\(\frac{1}{2}\) - 1\(\frac{1}{7}\) = [ 2\(\frac{5}{14}\)]