Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{4}{5}\) - \(\frac{3}{4}\) = [ \(\frac{1}{20}\)]

Q1) 1\(\frac{1}{2}\) - \(\frac{2}{3}\) = [ \(\frac{5}{6}\)]

Q1) 1\(\frac{2}{3}\) - 1\(\frac{3}{16}\) = [ \(\frac{23}{48}\)]

Q2) \(\frac{3}{7}\) - \(\frac{1}{3}\) = [ \(\frac{2}{21}\)]

Q2) 1\(\frac{1}{4}\) - \(\frac{2}{7}\) = [ \(\frac{27}{28}\)]

Q2) 3\(\frac{1}{3}\) - 2\(\frac{2}{3}\) = [ \(\frac{2}{3}\)]

Q3) \(\frac{9}{10}\) - \(\frac{1}{2}\) = [ \(\frac{2}{5}\)]

Q3) 1\(\frac{2}{5}\) - \(\frac{1}{2}\) = [ \(\frac{9}{10}\)]

Q3) 2\(\frac{1}{8}\) - 1\(\frac{4}{5}\) = [ \(\frac{13}{40}\)]

Q4) \(\frac{2}{3}\) - \(\frac{5}{8}\) = [ \(\frac{1}{24}\)]

Q4) 1\(\frac{1}{7}\) - \(\frac{3}{7}\) = [ \(\frac{5}{7}\)]

Q4) 2\(\frac{1}{3}\) - 1\(\frac{1}{6}\) = [ 1\(\frac{1}{6}\)]

Q5) \(\frac{6}{7}\) - \(\frac{1}{2}\) = [ \(\frac{5}{14}\)]

Q5) 1\(\frac{1}{2}\) - \(\frac{7}{8}\) = [ \(\frac{5}{8}\)]

Q5) 2\(\frac{1}{3}\) - 1\(\frac{9}{14}\) = [ \(\frac{29}{42}\)]

Q6) \(\frac{5}{7}\) - \(\frac{2}{3}\) = [ \(\frac{1}{21}\)]

Q6) 1\(\frac{1}{5}\) - \(\frac{5}{7}\) = [ \(\frac{17}{35}\)]

Q6) 4\(\frac{1}{2}\) - 1\(\frac{5}{16}\) = [ 3\(\frac{3}{16}\)]

Q7) \(\frac{1}{2}\) - \(\frac{3}{8}\) = [ \(\frac{1}{8}\)]

Q7) 1\(\frac{1}{2}\) - \(\frac{5}{6}\) = [ \(\frac{2}{3}\)]

Q7) 4\(\frac{1}{2}\) - 2\(\frac{2}{5}\) = [ 2\(\frac{1}{10}\)]

Q8) \(\frac{5}{6}\) - \(\frac{2}{3}\) = [ \(\frac{1}{6}\)]

Q8) 1\(\frac{3}{7}\) - \(\frac{2}{3}\) = [ \(\frac{16}{21}\)]

Q8) 2\(\frac{1}{3}\) - 1\(\frac{3}{5}\) = [ \(\frac{11}{15}\)]

Q9) \(\frac{4}{5}\) - \(\frac{7}{9}\) = [ \(\frac{1}{45}\)]

Q9) 1\(\frac{1}{5}\) - \(\frac{3}{4}\) = [ \(\frac{9}{20}\)]

Q9) 2\(\frac{1}{2}\) - 1\(\frac{1}{2}\) = [ 1]

Q10) \(\frac{1}{2}\) - \(\frac{1}{4}\) = [ \(\frac{1}{4}\)]

Q10) 1\(\frac{2}{5}\) - \(\frac{4}{5}\) = [ \(\frac{3}{5}\)]

Q10) 1\(\frac{7}{8}\) - 1\(\frac{1}{2}\) = [ \(\frac{3}{8}\)]