Mr Daniels Maths
Functions Inverse

Set 1

Set 2

Set 3

Q1) \(f(x) =3{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over3\)]

Q1) g(x) = \(x\over 4\) + 5. Find g'(x). [ \(g'(x) \)= \(4(x -5)\)]

Q1) h(x) =\(x^ 3 + 6\). Find h'(x). [ h'(x)= \( \sqrt[3]{x -6} \)]

Q2) \(h(x) =6{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over6\)]

Q2) h(x) = 8 x + 9. Find h'(x). [ \(h'(x) \)= \({x -9}\over8\)]

Q2) f(x) =\( 2 x^ 2 + 10\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x -10}\over 2} \)]

Q3) f(x) =x + 9. Find f'(x). [ f'(x) = x -9]

Q3) g(x) = \(x\over 7\) + 4. Find g'(x). [ \(g'(x) \)= \(7(x -4)\)]

Q3) g(x) =\( 10 x^ 2 -8\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x +8}\over 10} \)]

Q4) f(x) =x + 5. Find f'(x). [ f'(x) = x -5]

Q4) g(x) = \(x\over 8\) + 4. Find g'(x). [ \(g'(x) \)= \(8(x -4)\)]

Q4) h(x) =\( 5 x^ 2 -9\). Find h'(x). [ h'(x)= \( \sqrt[2]{{x +9}\over 5} \)]

Q5) \(f(x) =8{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over8\)]

Q5) h(x) = \(x\over 3\) -7. Find h'(x). [ \(h'(x) \)= \(3(x +7)\)]

Q5) h(x) =\(x^ 3 -6\). Find h'(x). [ h'(x)= \( \sqrt[3]{x +6} \)]

Q6) h(x) =x -7. Find h'(x). [ h'(x) = x +7]

Q6) g(x) = 7 x + 8. Find g'(x). [ \(g'(x) \)= \({x -8}\over7\)]

Q6) h(x) =\(x^ 2 + 7\). Find h'(x). [ h'(x)= \( \sqrt[2]{x -7} \)]

Q7) \(h(x) =5{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over5\)]

Q7) f(x) = 4 x -6. Find f'(x). [ \(f'(x) \)= \({x +6}\over4\)]

Q7) f(x) =\( 9 x^ 3 + 5\). Find f'(x). [ f'(x)= \( \sqrt[3]{{x -5}\over 9} \)]

Q8) \(h(x) =3{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over3\)]

Q8) f(x) = \(x\over 6\) + 6. Find f'(x). [ \(f'(x) \)= \(6(x -6)\)]

Q8) g(x) =\(x^ 2 + 7\). Find g'(x). [ g'(x)= \( \sqrt[2]{x -7} \)]

Q9) \(g(x) =10{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over10\)]

Q9) f(x) = \(x\over 8\) + 5. Find f'(x). [ \(f'(x) \)= \(8(x -5)\)]

Q9) f(x) =\( 10 x^ 2 -6\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x +6}\over 10} \)]

Q10) \(g(x) =3{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over3\)]

Q10) g(x) = \(x\over 8\) + 2. Find g'(x). [ \(g'(x) \)= \(8(x -2)\)]

Q10) g(x) =\( 5 x^ 3 + 9\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x -9}\over 5} \)]