Mr Daniels Maths
Functions Inverse

Set 1

Set 2

Set 3

Q1) f(x) =x -5. Find f'(x). [ f'(x) = x +5]

Q1) h(x) = x + 10. Find h'(x). [ \(h'(x) \)= \({x -10}\over1\)]

Q1) f(x) =\(x^ 2 -2\). Find f'(x). [ f'(x)= \( \sqrt[2]{x +2} \)]

Q2) \(g(x) =10{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over10\)]

Q2) f(x) = \(x\over 10\) -4. Find f'(x). [ \(f'(x) \)= \(10(x +4)\)]

Q2) f(x) =\( 2 x^ 2 + 2\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x -2}\over 2} \)]

Q3) h(x) =x -8. Find h'(x). [ h'(x) = x +8]

Q3) h(x) = \(x\over 3\) -2. Find h'(x). [ \(h'(x) \)= \(3(x +2)\)]

Q3) g(x) =\( 9 x^ 2 + 10\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x -10}\over 9} \)]

Q4) g(x) =x + 8. Find g'(x). [ g'(x) = x -8]

Q4) g(x) = 5 x + 7. Find g'(x). [ \(g'(x) \)= \({x -7}\over5\)]

Q4) g(x) =\( 8 x^ 3 + 2\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x -2}\over 8} \)]

Q5) \(h(x) =3{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over3\)]

Q5) h(x) = \(x\over 9\) + 6. Find h'(x). [ \(h'(x) \)= \(9(x -6)\)]

Q5) g(x) =\(x^ 3 -3\). Find g'(x). [ g'(x)= \( \sqrt[3]{x +3} \)]

Q6) h(x) =x + 9. Find h'(x). [ h'(x) = x -9]

Q6) f(x) = 2 x -6. Find f'(x). [ \(f'(x) \)= \({x +6}\over2\)]

Q6) h(x) =\( 4 x^ 2 + 3\). Find h'(x). [ h'(x)= \( \sqrt[2]{{x -3}\over 4} \)]

Q7) h(x) =x -2. Find h'(x). [ h'(x) = x +2]

Q7) h(x) = \(x\over 9\) + 3. Find h'(x). [ \(h'(x) \)= \(9(x -3)\)]

Q7) g(x) =\( 2 x^ 2 -8\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x +8}\over 2} \)]

Q8) \(f(x) =2{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over2\)]

Q8) g(x) = 9 x + 2. Find g'(x). [ \(g'(x) \)= \({x -2}\over9\)]

Q8) g(x) =\( 8 x^ 3 -7\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x +7}\over 8} \)]

Q9) \(g(x) =9{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over9\)]

Q9) h(x) = \(x\over 8\) + 2. Find h'(x). [ \(h'(x) \)= \(8(x -2)\)]

Q9) f(x) =\(x^ 3 -7\). Find f'(x). [ f'(x)= \( \sqrt[3]{x +7} \)]

Q10) \(h(x) =6{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over6\)]

Q10) g(x) = \(x\over 8\) + 5. Find g'(x). [ \(g'(x) \)= \(8(x -5)\)]

Q10) g(x) =\( 10 x^ 2 -9\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x +9}\over 10} \)]