Q1) 1\(\frac{2}{3}\) + 4\(\frac{1}{2}\) = [ 6\(\frac{1}{6}\)]

Q1) 2\(\frac{2}{3}\) - 1\(\frac{2}{9}\) = [ 1\(\frac{4}{9}\)]

Q1) 1\(\frac{4}{5}\) x 1\(\frac{1}{8}\) = [ 2\(\frac{1}{40}\)]

Q2) 1\(\frac{1}{3}\) + 1\(\frac{2}{7}\) = [ 2\(\frac{13}{21}\)]

Q2) 2\(\frac{1}{5}\) - 1\(\frac{5}{9}\) = [ \(\frac{29}{45}\)]

Q2) 3\(\frac{1}{2}\) \(\div\) 1\(\frac{2}{3}\) = [ 2\(\frac{1}{10}\)]

Q3) 1\(\frac{1}{3}\) + 1\(\frac{1}{6}\) = [ 2\(\frac{1}{2}\)]

Q3) 2\(\frac{3}{5}\) - 1\(\frac{1}{3}\) = [ 1\(\frac{4}{15}\)]

Q3) 2\(\frac{1}{4}\) x 3\(\frac{1}{3}\) = [ 7\(\frac{1}{2}\)]

Q4) 1\(\frac{3}{5}\) + 1\(\frac{1}{2}\) = [ 3\(\frac{1}{10}\)]

Q4) 3\(\frac{1}{2}\) - 1\(\frac{4}{11}\) = [ 2\(\frac{3}{22}\)]

Q4) 1\(\frac{1}{3}\) \(\div\) 2\(\frac{1}{4}\) = [ \(\frac{16}{27}\)]

Q5) 1\(\frac{1}{2}\) + 2\(\frac{1}{2}\) = [ 4]

Q5) 2\(\frac{2}{3}\) - 2\(\frac{1}{3}\) = [ \(\frac{1}{3}\)]

Q5) 1\(\frac{3}{4}\) \(\div\) 1\(\frac{1}{8}\) = [ 1\(\frac{5}{9}\)]

Q6) 2\(\frac{1}{3}\) + 1\(\frac{4}{5}\) = [ 4\(\frac{2}{15}\)]

Q6) 3\(\frac{2}{3}\) - 1\(\frac{2}{3}\) = [ 2]

Q6) 1\(\frac{1}{5}\) x 2\(\frac{1}{2}\) = [ 3]

Q7) 1\(\frac{1}{9}\) + 1\(\frac{1}{9}\) = [ 2\(\frac{2}{9}\)]

Q7) 2\(\frac{1}{9}\) - 1\(\frac{1}{2}\) = [ \(\frac{11}{18}\)]

Q7) 1\(\frac{1}{8}\) x 2\(\frac{1}{2}\) = [ 2\(\frac{13}{16}\)]

Q8) 1\(\frac{1}{7}\) + 2\(\frac{1}{4}\) = [ 3\(\frac{11}{28}\)]

Q8) 2\(\frac{1}{4}\) - 1\(\frac{5}{11}\) = [ \(\frac{35}{44}\)]

Q8) 1\(\frac{1}{4}\) x 1\(\frac{1}{7}\) = [ 1\(\frac{3}{7}\)]

Q9) 1\(\frac{2}{7}\) + 1\(\frac{2}{7}\) = [ 2\(\frac{4}{7}\)]

Q9) 2\(\frac{1}{3}\) - 1\(\frac{4}{5}\) = [ \(\frac{8}{15}\)]

Q9) 1\(\frac{2}{5}\) x 4\(\frac{1}{2}\) = [ 6\(\frac{3}{10}\)]

Q10) 1\(\frac{1}{2}\) + 1\(\frac{1}{5}\) = [ 2\(\frac{7}{10}\)]

Q10) 1\(\frac{5}{6}\) - 1\(\frac{2}{3}\) = [ \(\frac{1}{6}\)]

Q10) 1\(\frac{4}{5}\) x 1\(\frac{1}{2}\) = [ 2\(\frac{7}{10}\)]