Mr Daniels Maths
Mixed Numbers 4 Operations

Set 1

Set 2

Set 3

Q1) 3\(\frac{1}{2}\) + 1\(\frac{3}{7}\) = [ 4\(\frac{13}{14}\)]

Q1) 1\(\frac{8}{11}\) - 1\(\frac{2}{5}\) = [ \(\frac{18}{55}\)]

Q1) 2\(\frac{1}{4}\) x 1\(\frac{1}{2}\) = [ 3\(\frac{3}{8}\)]

Q2) 1\(\frac{1}{6}\) + 1\(\frac{1}{7}\) = [ 2\(\frac{13}{42}\)]

Q2) 3\(\frac{2}{3}\) - 1\(\frac{3}{5}\) = [ 2\(\frac{1}{15}\)]

Q2) 1\(\frac{2}{3}\) x 1\(\frac{1}{2}\) = [ 2\(\frac{1}{2}\)]

Q3) 1\(\frac{1}{5}\) + 1\(\frac{3}{5}\) = [ 2\(\frac{4}{5}\)]

Q3) 2\(\frac{1}{2}\) - 2\(\frac{1}{3}\) = [ \(\frac{1}{6}\)]

Q3) 3\(\frac{1}{2}\) x 1\(\frac{2}{3}\) = [ 5\(\frac{5}{6}\)]

Q4) 1\(\frac{3}{4}\) + 1\(\frac{2}{5}\) = [ 3\(\frac{3}{20}\)]

Q4) 2\(\frac{1}{3}\) - 1\(\frac{1}{3}\) = [ 1]

Q4) 1\(\frac{1}{3}\) x 1\(\frac{2}{7}\) = [ 1\(\frac{5}{7}\)]

Q5) 1\(\frac{1}{8}\) + 1\(\frac{4}{5}\) = [ 2\(\frac{37}{40}\)]

Q5) 2\(\frac{1}{2}\) - 1\(\frac{5}{8}\) = [ \(\frac{7}{8}\)]

Q5) 3\(\frac{1}{2}\) \(\div\) 1\(\frac{2}{7}\) = [ 2\(\frac{13}{18}\)]

Q6) 2\(\frac{2}{3}\) + 1\(\frac{2}{3}\) = [ 4\(\frac{1}{3}\)]

Q6) 2\(\frac{1}{2}\) - 1\(\frac{1}{3}\) = [ 1\(\frac{1}{6}\)]

Q6) 1\(\frac{1}{4}\) \(\div\) 1\(\frac{3}{4}\) = [ \(\frac{5}{7}\)]

Q7) 2\(\frac{1}{4}\) + 3\(\frac{1}{2}\) = [ 5\(\frac{3}{4}\)]

Q7) 3\(\frac{2}{3}\) - 1\(\frac{1}{3}\) = [ 2\(\frac{1}{3}\)]

Q7) 1\(\frac{2}{5}\) x 1\(\frac{1}{4}\) = [ 1\(\frac{3}{4}\)]

Q8) 2\(\frac{2}{3}\) + 2\(\frac{1}{3}\) = [ 5]

Q8) 3\(\frac{1}{4}\) - 2\(\frac{1}{8}\) = [ 1\(\frac{1}{8}\)]

Q8) 1\(\frac{3}{5}\) x 1\(\frac{1}{4}\) = [ 2]

Q9) 3\(\frac{1}{2}\) + 2\(\frac{1}{4}\) = [ 5\(\frac{3}{4}\)]

Q9) 2\(\frac{2}{5}\) - 1\(\frac{2}{5}\) = [ 1]

Q9) 3\(\frac{1}{3}\) \(\div\) 1\(\frac{1}{2}\) = [ 2\(\frac{2}{9}\)]

Q10) 1\(\frac{2}{7}\) + 2\(\frac{2}{3}\) = [ 3\(\frac{20}{21}\)]

Q10) 2\(\frac{2}{3}\) - 1\(\frac{2}{3}\) = [ 1]

Q10) 1\(\frac{3}{5}\) \(\div\) 1\(\frac{1}{8}\) = [ 1\(\frac{19}{45}\)]