Mr Daniels Maths
Simplifying Fractions

Set 1

Set 2

Set 3

Q1) \(9 \over 45\) = [ \(\frac{1}{5}\)]

Q1) \(18 \over 27\) = [ \(\frac{2}{3}\)]

Q1) \(54 \over 10\) = [ 5\(\frac{2}{5}\)]

Q2) \(7 \over 49\) = [ \(\frac{1}{7}\)]

Q2) \(80 \over 160\) = [ \(\frac{1}{2}\)]

Q2) \(28 \over 9\) = [ 3\(\frac{1}{9}\)]

Q3) \(8 \over 16\) = [ \(\frac{1}{2}\)]

Q3) \(40 \over 64\) = [ \(\frac{5}{8}\)]

Q3) \(14 \over 3\) = [ 4\(\frac{2}{3}\)]

Q4) \(5 \over 15\) = [ \(\frac{1}{3}\)]

Q4) \(54 \over 81\) = [ \(\frac{2}{3}\)]

Q4) \(8 \over 3\) = [ 2\(\frac{2}{3}\)]

Q5) \(8 \over 56\) = [ \(\frac{1}{7}\)]

Q5) \(56 \over 140\) = [ \(\frac{2}{5}\)]

Q5) \(20 \over 6\) = [ 3\(\frac{1}{3}\)]

Q6) \(2 \over 20\) = [ \(\frac{1}{10}\)]

Q6) \(18 \over 54\) = [ \(\frac{1}{3}\)]

Q6) \(9 \over 10\) = [ \(\frac{9}{10}\)]

Q7) \(7 \over 56\) = [ \(\frac{1}{8}\)]

Q7) \(144 \over 288\) = [ \(\frac{1}{2}\)]

Q7) \(25 \over 2\) = [ 12\(\frac{1}{2}\)]

Q8) \(5 \over 25\) = [ \(\frac{1}{5}\)]

Q8) \(20 \over 70\) = [ \(\frac{2}{7}\)]

Q8) \(16 \over 3\) = [ 5\(\frac{1}{3}\)]

Q9) \(3 \over 21\) = [ \(\frac{1}{7}\)]

Q9) \(108 \over 252\) = [ \(\frac{3}{7}\)]

Q9) \(6 \over 5\) = [ 1\(\frac{1}{5}\)]

Q10) \(10 \over 100\) = [ \(\frac{1}{10}\)]

Q10) \(48 \over 120\) = [ \(\frac{2}{5}\)]

Q10) \(15 \over 9\) = [ 1\(\frac{2}{3}\)]