Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \( {y\over10}+9 = 11\) [ \(y= 20\)]

Q1) \(4(w -4) = 24\) [ w= \(10\)]

Q1) 5(4z -8) = 60 [ z = 5]

Q2) \(14x -7 = 77\) [ \( x = 6\)]

Q2) \(6(w + 2) = 66\) [ w= \(9\)]

Q2) 2(8y -4) = 88 [ y = 6]

Q3) \(7y -4 = 10\) [ \( y = 2\)]

Q3) \(4(y + 3) = 32\) [ y= \(5\)]

Q3) 3(4z -5) = 69 [ z = 7]

Q4) \(7y -2 = 33\) [ \( y = 5\)]

Q4) \(7(x -2) = 21\) [ x= \(5\)]

Q4) 2(2x -3) = 34 [ x = 10]

Q5) \(5z -7 = 28\) [ \( z = 7\)]

Q5) \(5(x + 5) = 60\) [ x= \(7\)]

Q5) 6(2x -6) = 60 [ x = 8]

Q6) \(19z + 4 = 137\) [ \( z = 7\)]

Q6) \(4(y -5) = 20\) [ y= \(10\)]

Q6) 2(7w + 7) = 84 [ w = 5]

Q7) \(8y + 5 = 45\) [ \( y = 5\)]

Q7) \(3(w -7) = 6\) [ w= \(9\)]

Q7) 3(2y -10) = 24 [ y = 9]

Q8) \( {x\over4}+8 = 10\) [ \(x= 8\)]

Q8) \(10(x -4) = 50\) [ x= \(9\)]

Q8) 2(3y + 5) = 40 [ y = 5]

Q9) \( {w\over2}+2 = 6\) [ \(w= 8\)]

Q9) \(4(x -9) = 4\) [ x= \(10\)]

Q9) 2(3w + 10) = 32 [ w = 2]

Q10) \(7z + 6 = 41\) [ \( z = 5\)]

Q10) \(9(w + 9) = 171\) [ w= \(10\)]

Q10) 7(2y -3) = 77 [ y = 7]