Mr Daniels Maths
Surds:Division

Set 1

Set 2

Set 3

Q1) \(\sqrt 63 \over{ \sqrt{ 9}} \) = [ \(\sqrt{7}\)]

Q1) \(5 \sqrt 24 \over{ \sqrt 8} \) = [ \(5\sqrt{3}\)]

Q1) \(8 \sqrt 4 \over{ 2 \sqrt 2} \) = [ \(4\sqrt{2}\)]

Q2) \(\sqrt 6 \over{ \sqrt{ 3}} \) = [ \(\sqrt{2}\)]

Q2) \(4 \sqrt 63 \over{ \sqrt 9} \) = [ \(4\sqrt{7}\)]

Q2) \(20 \sqrt 20 \over{ 5 \sqrt 4} \) = [ \(4\sqrt{5}\)]

Q3) \(\sqrt 16 \over{ \sqrt{ 2}} \) = [ \(2\sqrt{2}\)]

Q3) \(5 \sqrt 80 \over{ \sqrt 10} \) = [ \(10\sqrt{2}\)]

Q3) \(16 \sqrt 15 \over{ 4 \sqrt 3} \) = [ \(4\sqrt{5}\)]

Q4) \(\sqrt 40 \over{ \sqrt{ 10}} \) = [ \(2\)]

Q4) \(2 \sqrt 9 \over{ \sqrt 3} \) = [ \(2\sqrt{3}\)]

Q4) \(16 \sqrt 8 \over{ 4 \sqrt 4} \) = [ \(4\sqrt{2}\)]

Q5) \(\sqrt 24 \over{ \sqrt{ 6}} \) = [ \(2\)]

Q5) \(2 \sqrt 56 \over{ \sqrt 7} \) = [ \(4\sqrt{2}\)]

Q5) \(25 \sqrt 8 \over{ 5 \sqrt 4} \) = [ \(5\sqrt{2}\)]

Q6) \(\sqrt 100 \over{ \sqrt{ 10}} \) = [ \(\sqrt{10}\)]

Q6) \(5 \sqrt 20 \over{ \sqrt 4} \) = [ \(5\sqrt{5}\)]

Q6) \(15 \sqrt 8 \over{ 5 \sqrt 4} \) = [ \(3\sqrt{2}\)]

Q7) \(\sqrt 8 \over{ \sqrt{ 2}} \) = [ \(2\)]

Q7) \(5 \sqrt 18 \over{ \sqrt 9} \) = [ \(5\sqrt{2}\)]

Q7) \(8 \sqrt 10 \over{ 4 \sqrt 5} \) = [ \(2\sqrt{2}\)]

Q8) \(\sqrt 72 \over{ \sqrt{ 8}} \) = [ \(3\)]

Q8) \(5 \sqrt 100 \over{ \sqrt 10} \) = [ \(5\sqrt{10}\)]

Q8) \(4 \sqrt 6 \over{ 2 \sqrt 3} \) = [ \(2\sqrt{2}\)]

Q9) \(\sqrt 24 \over{ \sqrt{ 4}} \) = [ \(\sqrt{6}\)]

Q9) \(3 \sqrt 8 \over{ \sqrt 4} \) = [ \(3\sqrt{2}\)]

Q9) \(6 \sqrt 1 \over{ 3 \sqrt 1} \) = [ \(2\)]

Q10) \(\sqrt 60 \over{ \sqrt{ 6}} \) = [ \(\sqrt{10}\)]

Q10) \(3 \sqrt 45 \over{ \sqrt 5} \) = [ \(9\)]

Q10) \(12 \sqrt 8 \over{ 4 \sqrt 4} \) = [ \(3\sqrt{2}\)]