Mr Daniels Maths
Surds Simplifying

Set 1

Set 2

Set 3

Q1) \(\sqrt{90}\) = [ \(3\sqrt{10}\)]

Q1) \(10 \sqrt 20 \over{ 5 \sqrt 4} \) = [ \(2\sqrt{5}\)]

Q1) \(\sqrt { 2 } \) + \(\sqrt { 8 }= \) [ \(3\sqrt{2}\)]

Q2) \(\sqrt{48}\) = [ \(4\sqrt{3}\)]

Q2) \(4\sqrt 4 \) x \(5\sqrt 9= \) [ \(120\)]

Q2) \(\sqrt { 320 } \) + \(\sqrt { 80 }= \) [ \(12\sqrt{5}\)]

Q3) \(\sqrt{28}\) = [ \(2\sqrt{7}\)]

Q3) \(10 \sqrt 12 \over{ 5 \sqrt 6} \) = [ \(2\sqrt{2}\)]

Q3) \(\sqrt { 18 } \) - \(\sqrt { 8 }= \) [ \(\sqrt{2}\)]

Q4) \(\sqrt{72}\) = [ \(6\sqrt{2}\)]

Q4) \(4\sqrt 9 \) x \(4\sqrt 8= \) [ \(96\sqrt{2}\)]

Q4) \(\sqrt { 128 } \) + \(\sqrt { 128 }= \) [ \(16\sqrt{2}\)]

Q5) \(\sqrt{80}\) = [ \(4\sqrt{5}\)]

Q5) \(4\sqrt 2 \) x \(5\sqrt 3= \) [ \(20\sqrt{6}\)]

Q5) \(\sqrt { 192 } \) - \(\sqrt { 12 }= \) [ \(6\sqrt{3}\)]

Q6) \(\sqrt{128}\) = [ \(8\sqrt{2}\)]

Q6) \(3\sqrt 3 \) x \(5\sqrt 9= \) [ \(45\sqrt{3}\)]

Q6) \(\sqrt { 320 } \) + \(\sqrt { 500 }= \) [ \(18\sqrt{5}\)]

Q7) \(\sqrt{150}\) = [ \(5\sqrt{6}\)]

Q7) \(25 \sqrt 70 \over{ 5 \sqrt 10} \) = [ \(5\sqrt{7}\)]

Q7) \(\sqrt { 192 } \) - \(\sqrt { 108 }= \) [ \(2\sqrt{3}\)]

Q8) \(\sqrt{8}\) = [ \(2\sqrt{2}\)]

Q8) \(6 \sqrt 25 \over{ 3 \sqrt 5} \) = [ \(2\sqrt{5}\)]

Q8) \(\sqrt { 98 } \) - \(\sqrt { 50 }= \) [ \(2\sqrt{2}\)]

Q9) \(\sqrt{54}\) = [ \(3\sqrt{6}\)]

Q9) \(10 \sqrt 64 \over{ 5 \sqrt 8} \) = [ \(4\sqrt{2}\)]

Q9) \(\sqrt { 125 } \) - \(\sqrt { 20 }= \) [ \(3\sqrt{5}\)]

Q10) \(\sqrt{96}\) = [ \(4\sqrt{6}\)]

Q10) \(3\sqrt 10 \) x \(2\sqrt 2= \) [ \(12\sqrt{5}\)]

Q10) \(\sqrt { 300 } \) - \(\sqrt { 147 }= \) [ \(3\sqrt{3}\)]